Bagudu declared winner of Kebbi governorship election

 Bagudu



Governor Abubakar Atiku Bagudu has been declared winner of the governorship election in Kebbi State.

The presiding officer, professor Armu Yau Hamisu, said Bagudu of the All Progressives Congress (APC) emerged winner in the election, having scored the highest number of votes 673,717 with a difference of 567,084 against the 106,633 votes scored by the Peoples Democratic Party’s candidate, Senator Isa Galaudu, in the election.




The returning officer said the total registered voters is 1,789,075 while a total of 820078 were accredited for the election.

He said the total votes cast in the election was 814,084 while a total of 20,696 were rejected.




He said the “APC candidate, Abubakar Atiku Bagudu, having scored the highest number of votes in the election is hereby declared winner and returned”.

The APC candidate defeated his PDP opponent in all the 21 local government areas of the state.

Breakdown:

Yauri
APC-25,011
PDP-1,574

Arewa
APC-35,991
PDP-10,994

Gwandu
APC – 30,720
PDP -4,,526

Birnin Kebbi
APC-79,092
PDP-6010

Argungu
APC- 30101
PDP-23,397

Aliero
APC-21,923
PDP-3,479

Suru
APC -39,359
PDP-5,198

Shanga
APC-27,012
PDP-3,506

Kalgo
APC-21,899
PDP-805

Augie
APC-28,479
PDP-11,875

Bunza
APC- 23,980
PDP-2114

Dandi
APC-33,315
PDP-5,929

Sakaba
APC-19,182
PDP-1,746

Zuru
APC-25,507
PDP-4578

Jega
APC-53,807
PDP-1774

Maiyanma
APC-40,217
PDP-1,477

Bagudo
APC-41,556
PDP-2,581

Ngaski
APC-20,917
PDP-5,516

Fakai
APC-14,722
PDP-3,729

Danko-Wasagu
APC-29,625
PDP- 4,609

Koko/Besse
APC- 31,392
PDP-1,216

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